CREATING 5 NODES OF SINGLY LINKED LIST

AIM: To create 5 nodes for implementing singly linked list using c.
PROGRAM:
#include
#include
typedef struct Node
{
 int data;
 struct Node *next;
}node;
void insert(node *pointer, int data)
{
 while(pointer->next!=NULL)
 {
 pointer = pointer -> next;
 }
 pointer->next = (node *)malloc(sizeof(node));
 pointer = pointer->next;
 pointer->data = data;
 pointer->next = NULL;
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}
void print(node *pointer)
{
 if(pointer==NULL)
 {
 return;
 }
 printf(“%d “,pointer->data);
 print(pointer->next);
}
int main()
{
 int i;
 node *start,*temp;
 start = (node *)malloc(sizeof(node));
 temp = start;
 temp -> next = NULL;
 printf(“1. Insert\n”);
 printf(“2. Print\n”);
 while(1)
 {
 int query;
 scanf(“%d”,&query);
 if(query==1)
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 {
 printf(“\nEnter 5 nodes”);
 for(i=1;i<=5;i++)
 {
 int data;
 scanf(“%d”,&data);
 insert(start,data);
 }
 }